微分方方程式を解いて下さいdx/xz-y=dy/yz-x=dz/1-z^2

dx/xz-y=dy/yz-x=dz/1-z^2

dx+dy/(x+y)=dx/-(z+1)

log(x+y)=-log(z+1)=c

(x+y)(z+1)=c1

dx-dy/(x-y)=-dz/(z-1)

log(x-y)=-log(z-1)+c

(x-y)(z-1)=c2

--\u0026gt;

(x+y)(z+1)=c1

(x-y)(z-1)=c2