微分方方程式を解いて下さいdx/x-2y=dy/y-2x=dz/x^2-y^2

dx/x-2y=dy/y-2x=dz/x^2-y^2

dy/dx=(y-2x)/(x-2y)

y=xu

du(1-2u)/(u^2-1)=2dx/x

1/(u+1)^3(u-1)=cx^4

--\u0026gt;

(x-y)(x+y)^3=c1

xdx-ydy-dz/0 x^2-y^2=2z+c2