微分方方程式を解いて下さいdx/(b-c)yz=dy/(c-a)zx=dz/(a-b)xy

adx/(b-c)yz=bdy/(c-a)zx=cdz/(a-b)xy

axdx+bydy+czdz/0

ax^2+by^2+cz^2=c1

a^2xdx+b^2ydy+c^2zdz/0

a^2x^2+b^2y^2+c^2z^2=c2

--\u0026gt;

ax^2+by^2+cz^2=c1

a^2x^2+b^2y^2+c^2z^2=c2